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4x^2+81x-63=0
a = 4; b = 81; c = -63;
Δ = b2-4ac
Δ = 812-4·4·(-63)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-87}{2*4}=\frac{-168}{8} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+87}{2*4}=\frac{6}{8} =3/4 $
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